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Questions to be answered

  1. The current division equation (Equation gif) does not include the resistance of the ammeter. Let the internal resistance of the ammeter be . Write the expression for the current through , , including the resistance of the meter assuming that the ammeter is being used to measure the current . Then take the limit of this expression as the ammeter internal resistance goes to zero, showing that the limit is given by Equation gif.
  2. The voltage source and 10 k resistor in Figure gif form an approximate current source for small load resistances. If the voltage source and 10 k resistor formed an ideal current source, then the current would be constant, independent of the resistances of and , which is certainly not the case. Consider the parallel combination of and as a single resistance . If is small compared to 10 k, then the current will be very nearly 1 mA (Recall that ) independent of . Calculate the range of values of such that the current will deviate from 1 mA by no more than 5%.
  3. Consider the circuit shown in Figure gif. Suppose you want to know the value of all voltages and currents in the circuit. Assume that you know nothing at all about the resistor values. You want the results to be as accurate as possible. You have a multimeter that you may use as either a voltmeter or an ammeter. Explain the sequence of measurements that you make. Comment on your level of confidence that your results are accurate. Don't forget that you have Ohm's Law and Kirchhoff's Laws that may be used.

  
Figure: Resistive Network



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